It means that the species has completely filled valence orbitals.
How would Mg change to gain a noble gas structure?
Yes it does. Each fluorine shares one electron with oxygen. So fluorine as well as oxygen will have 8 valence electrons.
Krypton (Kr) has the same Lewis structure as Se2. Both molecules have 16 valence electrons arranged in a linear structure with a single covalent bond.
In a molecule of hydrogen chloride (HCl), the hydrogen atom attains a noble gas electron structure by sharing its electron with the chlorine atom, which attains a noble gas structure through the addition of the shared electron. The resulting electron structure mimics that of a noble gas (helium for hydrogen and argon for chlorine), fulfilling the octet rule for both atoms.
Yes, the electron structure of a zinc ion (Zn2+) achieves a pseudo noble gas configuration by losing two electrons to have a full outer shell, similar to a noble gas configuration. This stable electron configuration is in line with the octet rule, making it an example of pseudo noble gas formation.
A calcium atom must lose 2 electrons to achieve a noble gas structure, as it will then have the same electron configuration as argon, a noble gas. This loss of electrons allows the calcium atom to have a full outermost electron shell, giving it greater stability.
Atoms will gain, lose, or share electrons to match the number of outer shell electrons of a noble gas.
Barium, a group 2 metal, would lose two electrons to achieve a stable noble gas structure like xenon. This would result in a full valence shell and stability, similar to a noble gas atom.
It depends on what you mean by great. If you mean most massive, then radon has the biggest naturally occurring ones. ( However element 118 has been made artificially). If you mean the most common, then it is argon.
No, it is a noble gas
What relationship exists between the electron structure of Group IA ion and the electron structure of the nearest Noble Gas?
It must lose two electrons.