L and N orbit M
By pressing Y or M. But there is a very long delay between shots.
bhaar m ja
88 days it takes mercury to orbit the sun
The formula to find the orbital speed v for a satellite in a circular orbit of radius r is v (G M / r), where G is the gravitational constant, M is the mass of the central body, and r is the radius of the orbit.
17,580 mph or 7,860 s/m (in orbit)
Donald M. Waltz has written: 'On-orbit servicing of space systems' -- subject(s): Maintenance and repair, Space vehicles
Mars travels at somewhere around 24,000 m/s in its orbit around the sun. You can work this out by finding the distance of Mars to the Sun (the radius of orbit), finding the total distance of orbit (multiply your radius by 2*pi - assuming a circular orbit, which is ROUGHLY a good approximation), then divide by length of a Mars year. Enjoy.
It was not an asteroid. It was a planet. The name starts with an 'M'.
The centripetal acceleration of the Earth in its orbit around the Sun is approximately 0.0059 m/s². It is directed towards the center of the Sun and keeps the Earth moving in its circular path. This acceleration is necessary to counterbalance the gravitational force between the Earth and the Sun.
Satellites can orbit at different altitudes depending on their purpose. Low Earth Orbit (LEO) satellites typically orbit from 160 to 2,000 kilometers above the Earth's surface, while geostationary satellites are much higher, at about 35,786 kilometers. Various factors like communication, weather monitoring, or surveillance determine the satellite's optimal orbit.
Thomas M. Carson has written: 'The use of lunar beacons in lunar orbit estimation' -- subject(s): Artificial satellites, Kalman filtering, Navigation (Astronautics), Orbits
There is only one geostationary orbit because in order for any mass m to orbit the Earth (ME) the gravitational force: EQ1: Fg = GmME/r^2 has to be such that it is equal to the required centripetal force for uniform circular motion: EQ2: Fc = mv^2/r where v is the velocity of m at radius r (distance from the center of the Earth) and: EQ3: v = 2(pi)(r)(f) f is the frequency of rotation in revolutions per second. For geostationary orbit the satellite must be in a fixed position (it must have the same frequency of rotation or angular velocity as the Earth's rotation) relative to the Earth and orbit above the Earth's equator. The necessary velocity to satisfy Fg = Fc is a specific value, therefore (since pi and f are fixed values) r is the only variable in EQ3. There is a specific orbital radius for geostationary orbit of any mass m.