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V=Q/4πϵoa - Q/4πϵob
direction-along the axis of dipole from -q to +q.
This question requires the rearranging of several formulas in order to find the equations (there are two of them) to calculate the work needed to move a charge into the direction of an electric field.Symbols used in the following formulas.d = distance in meters (m).V = potential difference in volts (V).W = work in joules (J).q = charge in coulombs (C)E = electric field in Newtons per coulomb (N/C)Composing the formulaStep one) E = V ÷ dStep two) We know that w = qv, which we can then solve to produceV = w ÷ qStep three) If we then input the second formula into the first, we can get a formula to calculate the work needed to move a charge into the direction of an electric field,i.e.E = V ÷ d= E = (w ÷ q) ÷ dwhich simplifies to becomeE = w ÷ qdStep Four We can then solve this new formula to produce our desired formula which will be,w = qdE
1 Ampere = 1 Coulomb per second0.25 A = 0.25 Coulomb per sec1 minute = 60 seconds20 minutes = (20 x 60) = 1,200 seconds0.25 A for 20 minutes = (0.25 x 1,200) = 300 Amp-seconds = 300 Coulombs of charge
Coulombs for charge or Joules for heat capacity
If you know the electric current, the flow of electric charge through an object, traveling through a circuit and how long the current is applied, you can calculate electrical charge using the equation for current Q = It in which Q is the total charge measured in coulombs, I is current in amps, and t is time that the ..
When charges (means charged bodies) move , then we say that an electric current is produced. If charges remain at rest, current is zero. If charge Q moves through a metal in time t , then current I through metal is: I=Q/t; moreever, electric current can also be produced by rate of change of magnetic field through a metal...,
I=0.4 A T=3hrs=10800 seconDs i=q/t q=It q=0.4*10800 q=4320Coulomb
A coulomb is a measure of charge and current is the rate of flow of charge.There is a formula linking the three quantities (charge=Q; T=time; I=current):Q=I x T -> 1.5A x 0.1s= 0.15C
q=it so q=12 x (300sec) = 3600 C
Electric current is the flow of charge from one place to another. Charge is carried by electrons, so current can be defined as the number of electrons per second that pass through a given area.
The formula for the electric current can be given as I= Qt where Q refers to coulomb charge and t= amount of time in second . By applying this formula the amount of current passing through the conductor can be known foor any instant of time. For any conductor the amount of charge is always constant. Current measures the flow of moving charge per unit time. Therefore the formula for current is I=Q/t as the unit of current is C/s (Coulomb's per sec) or amps (A).
q is the amount of heat.. that formula is used in finding heat problems
Q1:How to calculate electric potential due to a dipole? Q2:How to calculate electric potential due to ring of charges? Q3:How to calculate electric potential due to charge disk? Q4:how to calculate electric potential due to a quadrupole?
Essentially yes. Where there is electric energy there is magnetic energy.Electric Energy E= QV = IW where Q is charge and V is volts and I is current and W is Webers. QV is electric energy and IW is magnetic Energy.
i do not understand your Q. i do not understand your Q.
As current is the rate of flow of electric chargesAs I=Q/tso,there must be free electrons for the flow of electric current in a circuit.Then when voltage is applied at the terminals of circuit the free electrons acquire an average velocity called as drift velocity in the opposite direction to that of electric field (-E).Now the free electrons modify there random motion and a steady current begin to flow in a circuit.