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What does L1 mean?
This word stand for Line1 <<>> On electrical equipment the terminal L1 is where the placement of the supply conductor is terminated. On three phase equipment, the terminals are identified as L1, L2 and L3. On an electrical magnetic contactor these terminals will be located on the top of the device. The terminations on the bottom of the device where the load is connected are designated T1 and again for a three phase equipment the designation would be T1, T2 and T3.
How big in Melbourne airport?
It's fairly big, but not scary like Heathrow or LAX, and very efficient. There are 4 terminals, T1 is Qantas & Jetstar domestic, T2 is International, T3 is Virgin Australia and REX domestic and T4 is Tiger domestic.
What is net heat change in polytropic process?
q=c(T2-T1)
How can temperature be measured by determining the change in volume?
P1/t1=p2/t2
Model paper of msc chemistry in ou?
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]
Timing diagram of shld 16 bit instruction?
The SHLD (Store H&L Direct) instruction takes 5 machine cycles and 16 clock states, not including any wait states. Opcode fetch: T1, T2, T3, and TX Low order address fetch: T1, T2, T3 High order address fetch: T1, T2, T3 Store L: T1, T2, T3 Store H: T1, T2, T3
Write a program to represent a polynomial as linked list and write functions for polynimial addition?
#include<iostream.h> #include<stdlib.h> #include<conio.h> struct poly { int coeff; int x; int y; int z; struct poly * next; }; class polynomial { private : poly *head; public: polynomial():head(NULL) { } void getdata(); void display(); void insert(poly *prv,poly *curr,poly *p); polynomial operator + (polynomial ); }; polynomial polynomial :: operator +(polynomial px2) { polynomial px; poly *t1,*t2,*t3,*last; t1 = head; t2 = px2.head; px.head = NULL; while(t1 != NULL && t2 != NULL) { t3 = new poly; t3->next = NULL; if(t1->x t2->z) { t3->coeff = t1->coeff + t2->coeff; t3->x = t1->x; t3->y = t1->y; t3->z = t1->z; t1 = t1->next; t2 = t2->next; } elseif(t1->x > t2->x) { t3->coeff = t1->coeff; t3->x = t1->x; t3->y = t1->y; t3->z = t1->z; t1 = t1->next; } elseif(t1->x < t2->x) { t3->coeff = t2->coeff; t3->x = t2->x; t3->y = t2->y; t3->z = t2->z; t2 = t2->next; } elseif(t1->y > t2->y) { t3->coeff = t1->coeff; t3->x = t1->x; t3->y = t1->y; t3->z = t1->z; t1 = t1->next; } elseif(t1->y < t2->y) { t3->coeff = t2->coeff; t3->x = t2->x; t3->y = t2->y; t3->z = t2->z; t2 = t2->next; } elseif(t1->z > t2->z) { t3->coeff = t1->coeff; t3->x = t1->x; t3->y = t1->y; t3->z = t1->z; t1 = t1->next; } elseif(t1->z < t2->z) { t3->coeff = t2->coeff; t3->x = t2->x; t3->y = t2->y; t3->z = t2->z; t2 = t2->next; } if(px.head == NULL) px.head = t3; else last->next = t3; last = t3; } if(t1 == NULL) t3->next = t2; else t3->next = t1; return px; } void polynomial :: insert(poly *prv,poly *curr,poly *node) { if(node->x curr->z) { curr->coeff += node->coeff; delete node; } elseif((node->x > curr->x) (node->x curr->y && node->z > curr->z)) { node->next = curr; prv->next = node; } else { prv = curr; curr = curr->next; if(curr == NULL) { prv->next = node; node->next = NULL; return; } insert(prv,curr,node); } return; } void polynomial :: getdata() { int tempcoeff; poly *node; while(1) { cout << endl << "Coefficient : "; cin >> tempcoeff; if (tempcoeff==0) break; node = new poly; node->coeff = tempcoeff; cout << endl << "Power of X : "; cin >> node->x; cout << endl << "Power of Y : "; cin >> node->y; cout << endl << "Power of Z : "; cin >> node->z; if(head == NULL) { node->next = NULL; head = node; } elseif(node->x head->z) { head->coeff += node->coeff; delete node; } elseif((node->x > head->x) (node->x head->y && node->z > head->z)) { node->next = head; head = node; } elseif (head->next == NULL) { head->next = node; node->next = NULL; } else insert(head,head->next,node); } } void polynomial :: display() { poly *temp; temp = head; cout << endl << "Polynomial :: "; while(temp != NULL) { if(temp->coeff < 0) cout << " - "; cout << abs(temp->coeff); if(temp->x != 0) cout << "x^" << temp->x; if(temp->y != 0) cout << "y^" << temp->y; if(temp->z != 0) cout << "z^" << temp->z; if(temp->next->coeff > 0) cout << " + "; temp = temp->next; } cout << " = 0"; } void main() { polynomial px1,px2,px3; clrscr(); px1.getdata(); px2.getdata(); px3 = px1 + px2; px1.display(); px2.display(); px3.display(); getch(); }
Surface area of a triangle?
T1= t2= t3= t4= r=
Justin has 3 pairs of trouses 2 shirts and 2 pairs of boots How many different outfits can he wear?
t1 s1 b1 t1 s1 b2 t1 s2 b1 t1 s2 b2 t2 s1 b1 t2 s1 b2 t2 s2 b1 t2 s2 b2 t3 s1 b1 t3 s1 b2 t3 s2 b1 t3 s2 b2 TOTAL 12 combinations OR 2(3 x 2) = 12
What is the mathematical expression for the third law of thermodynamics?
The third law could be expressed as: If T1 = T2 and T2 = T3, then T1 = T3. Where T1 is the temperature of system (or object) 1. T2 is the temperature of system (or object) 2. T3 is the temperature of system (or object) 3. That may seem trivial from an algebraic standpoint but it has profound implications in thermodynamics because it helps define the meaning of temperature and thermal equilibrium.
How to use threads simultaneously?
Threads are meant to be used simultaneously. If you have 3 threads, you can run them simultaneously by starting them together. Ex: t1.start(); t2.start(); t3.start(); Assuming the three threads t1, t2 and t3 are already created.
What does compound interest and exponential growth share?
The ratio of the quantity between two sets of time an equal period apart are the same. That is, the rate of growth over the same time is a constant. Suppose V(t) is the value of the variable V at time t. Then, if t1, t2, t3 and t4 are four times such that t2 - t1 = t4 - t3 then V(t2)/V(t1) = V(t4)/V(t3) whether V is compound interest or exponential growth.
Which side of a motor contactor should the overload contact be placed?
On the load side of the contactor. T1,T2,T3.
What are the differences between a T1 and a T3 leased line?
T1 and T2 are two common types of lease lines in telecommunications. T1 is the standard and was developed by AT&T. T3 are often used for long-distance traffic and to build the core of a business network headquarters.
Is T1 still the standard?
Although T1 is still used it is not the standard anymore. Currently there are faster internet access available for business like T2 and T3
What are the first four terms of the geometric sequence with a t1 equals 3 and tn equals 2tn-1?
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24
6 Fetching and decoding of any instruction takes three clock cycles How?
Incorrect. Fetching and decoding of any instruction takes a minimum of four clock cycles in the 8085. T1 = ALE and address emission T2 = Read initiation T3 = Read completion T4 = Opcode decode T1, T2, and T3 are repeated for each additional byte of the instruction. In all cases, Twait, if indicated by not READY, is inserted between T2 and T3.
