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Q: What does the Germany cout of arms mean?
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Write an application that displays in the command window a box an oval an arrow and a diamond using asterisks as follows?

the code for the box is: # include <iostream> using namespace std; void main () { cout << "*********\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*\t*\n"; cout << "*********\n"; the code for the oval is: # include <iostream> using namespace std; void main () { cout << " ***\n"; cout <<" * *\n"; cout <<"* *\n"; cout <<"* *\n"; cout <<"* *\n"; cout <<"* *\n"; cout <<"* *\n"; cout <<" * *\n"; cout << " ***\n"; the code for the arrow is: # include <iostream> using namespace std; void main () { cout << " * \n"; cout <<" ***\n"; cout <<"*****\n"; cout <<" * \n"; cout <<" * \n"; cout <<" * \n"; cout <<" * \n"; cout <<" * \n"; the code for the diamond: # include <iostream> using namespace std; void main () { cout << " *\n "; cout <<" * *\n"; cout<<" * *\n"; cout<<" * *\n"; cout<<"* *\n"; cout<<" * *\n"; cout<<" * *\n"; cout <<" * *\n"; cout << " *\n "; }


What does Germany's coat of arms represent?

Germany's coat of arms shows a black eagle on a yellow background. Since 1990, it has been symbolic of a reunified Germany.


Who was involved in the arms race?

Germany and Britain.


What is the definition of cout?

COUT is an inbuilt function in c++ language. Cout is used to print something on to the standard output.


Decision of a judge or cout?

This is an incomplete sentence, and "cout" is not a word.


How do you print 1 to 100 in c without using loop condition?

If you mean you cannot use a for loop, then use a while loop: int i=0 while( i++ < 100 ) std::cout << i << " "; std::cout << std::endl; Or a do-while loop: int i=0; do std::cout << ++i << " "; while( i<100 ); std::cout << std::endl; If these are not allowed either, use a procedural loop: int i=0; again: std::cout << ++i << " "; if( i<100 ) goto again; std::cout << std::endl; If even that is not allowed, then the only option is to hard-wire: std::cout << 1 << " " << 2 << " " << [etc] << 99 << " " << 100 << std::endl; It does seem a pointless exercise when a for loop exists specifically for counting iterations like this: for( int i=1; i<=100; ++i ) std::cout << i << " "; std::cout << std::endl;


What is the national bird and animal of Germany?

It´s an eagle. It´s on the Coat of arms of Germany.


What is pointing program?

// Pointing // Demonstrates using pointers #include <iostream> #include <string> using namespace std; int main() { int* pAPointer; //declare a pointer int* pScore = 0; //declare and initialize a pointer int score = 1000; pScore = &score; //assign pointer pScore address of variable score cout << "Assigning &score to pScore\n"; cout << "&score is: " << &score << "\n"; //address of score variable cout << "pScore is: " << pScore << "\n"; //address stored in pointer cout << "score is: " << score << "\n"; cout << "*pScore is: " << *pScore << "\n\n"; //value pointed to by pointer cout << "Adding 500 to score\n"; score += 500; cout << "score is: " << score << "\n"; cout << "*pScore is: " << *pScore << "\n\n"; cout << "Adding 500 to *pScore\n"; *pScore += 500; cout << "score is: " << score << "\n"; cout << "*pScore is: " << *pScore << "\n\n"; cout << "Assigning &newScore to pScore\n"; int newScore = 5000; pScore = &newScore; cout << "&newScore is: " << &newScore << "\n"; cout << "pScore is: " << pScore << "\n"; cout << "newScore is: " << newScore << "\n"; cout << "*pScore is: " << *pScore << "\n\n"; cout << "Assigning &str to pStr\n"; string str = "score"; string* pStr = &str; //pointer to string object cout << "str is: " << str << "\n"; cout << "*pStr is: " << *pStr << "\n"; cout << "(*pStr).size() is: " << (*pStr).size() << "\n"; cout << "pStr->size() is: " << pStr->size() << "\n"; return 0; }


What are mid libs c plus plus?

// Mad-Lib // Creates a story based on user input #include <iostream> #include <string> using namespace std; string askText(string prompt); int askNumber(string prompt); void tellStory(string name, string noun, int number, string bodyPart, string verb); int main() { cout << "Welcome to Mad Lib.\n\n"; cout << "Answer the following questions to help create a new story.\n"; string name = askText("Please enter a name: "); string noun = askText("Please enter a plural noun: "); int number = askNumber("Please enter a number: "); string bodyPart = askText("Please enter a body part: "); string verb = askText("Please enter a verb: "); tellStory(name, noun, number, bodyPart, verb); return 0; } string askText(string prompt) { string text; cout << prompt; cin >> text; return text; } int askNumber(string prompt) { int num; cout << prompt; cin >> num; return num; } void tellStory(string name, string noun, int number, string bodyPart, string verb) { cout << "\nHere's your story:\n"; cout << "The famous explorer "; cout << name; cout << " had nearly given up a life-long quest to find\n"; cout << "The Lost City of "; cout << noun; cout << " when one day, the "; cout << noun; cout << " found the explorer.\n"; cout << "Surrounded by "; cout << number; cout << " " << noun; cout << ", a tear came to "; cout << name << "'s "; cout << bodyPart << ".\n"; cout << "After all this time, the quest was finally over. "; cout << "And then, the "; cout << noun << "\n"; cout << "promptly devoured "; cout << name << ". "; cout << "The moral of the story? Be careful what you "; cout << verb; cout << " for."; }


Why cin and cout are not consider as keywords?

cin and cout are iostream objects, not keywords.


Write a program to print grade of a student in C?

#include<iostream.h> #include<conio.h> void main() { clrscr(); int marks; cout<<"Enter Marks of Student="; cin>>marks; cout<<"Grade\n"; if(marks>0 && marks<50) cout<<"F"; else if(marks>=50 && marks<55) cout<<"C-"; else if(marks>=55 && marks<60) cout<<"C"; else if(marks>=60 && marks<65) cout<<"c+"; else of(marks>=65 && marks<69) cout<<"B-"; else if(marks>=69 && marks<71) cout<<"B"; else if(marks>=71 && marks<75) cout<<"B+"; else if(marks>=75 && marks<79) cout<<"B"; else if(marks>=79 && marks<84) cout<<"A"; else cout<<"A"; getch(); }


What does code is case-sensitive mean when it is all numerical?

It means that you are writing code computer generates different names for x and X, also it will understand commands or will not under stand it at all (c++: cout and Cout are different).