Aluminum, Al, has 13 electrons. It is in period 3 and group 3A, so it is a P block element with 3 valence electrons. The ground state configuration would be 1s2 2s2 2p6 3s3
1s2, 2s2 2p6, 3s2 3p1or[Ne], 3s2 3p1
If it is in row 4 (4th period) it has 4 energy levels occupies. In the 2nd column (group 2A) it has 2 valence electrons. You ask how many orbitals it has. It has s and p orbitals. Is that what you mean? The configuration is 1s2 2s2 2p6 3s2 3p6 4s2 so there are 3 s orbitals and 6 p orbitals for a total of 9 orbitals.
[He] 2s2 2p6
1s2, 2s2, 2p6, 3s2, 3p1. If you do not know spdf-notation, it would 2, 8, 3.
1s2 2s2 2p6 3s2 3p3 or [Ne] 3s2 3p3
It's impossible, there are only 6 electrons in the p-orbital. So do you mean1s2 2s2 2p6? That's Neon.or do you mean1s2 2s2 2p6 3s1?That's Na, or Sodium.
1s2 2s2 2p6 3s2 3p6 4s2 3d6 That is for an iron atom. If you mean an Fe+3 ion 1s2 2s2 2p6 3s2 3p6 3d5
P is Phosphorus 1s2 2s2 2p6 3s2 3p3 or [Ne] 3s2 3p3
6 electrons in the p sublevel1s2 2s2 2p6 3s2 3p5
1s2 2s2 2p6 and is N3- nitrate
17. The electronic configuration of bromine is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 4p5
Aluminum, Al, has 13 electrons. It is in period 3 and group 3A, so it is a P block element with 3 valence electrons. The ground state configuration would be 1s2 2s2 2p6 3s3
The investigator will find that 1s2 2s2 2p6 is the electron configuration for neon.
cs2Electronic Configurationc6=1s2, 2s2, 2p6 s16=1s2, 2s2, 2p6, 3s2, 3p6s16=1s2, 2s2, 2p6, 3s2, 3p6
They are letters. s, p, and d 2s2 2p6 3s2 3p6 3d10 A full n = 3 level.
All three 2p orbitals (2px, 2py, 2pz) are occupied by two electrons each.(6 electrons in total: (2px2, 2py2, 2pz2) = 2p6)