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As the coin submerged in water and kept at the bottom of the vessel and if it is looked right from the top then it will appear to be lifted up by a small distance such that the actual depth / apparent depth = refractive index of water. If suppose the actual height of level of water is 12 cm then the coim will be shifted up by 3 cm. So the apparent depth will be 9 cm. Hence refractive index of water = 12/9 = 4/3 = 1.333.

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Q: What does the coin that lies submerged at the bottom part of water looks?
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