You will find that it will separate into two ions:hydrogen (H+) and hydroxyl (OH-).
Dissociation of sodium chloride in water solution: NaCl -----------Na+ + Cl-
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The balanced equation for the dissociation of water is: 2H2O (liquid) ⇌ 2H+ (aqueous) + O2- (aqueous)
The acid dissociation constant (Ka) for an acid dissolved in water is the equilibrium constant for the dissociation reaction of the acid into its ion components in water. It represents the extent of the acid's ionization in water.
The equilibrium constant for the dissociation of acetic acid in water is known as the acid dissociation constant (Ka) and is approximately 1.8 x 10-5.
hydrogen and water
Another way to describe the dissociation of water is as follows where two water molecules form a hydronium ion (essentially a water molecule with a proton attached) and a hydroxide ion
The dissociation constant of pure water is 1.9E-5.
The acid dissociation constant (Ka) for an acid dissolved in water is equal to the ratio of the concentration of the products (H+ and the conjugate base) over the concentration of the reactant (the acid). It represents the extent of dissociation of the acid in water.
This is a "reaction" with water, a dissociation of the salt in ions.
dissociation
Ions: H+ and OH-.