H stands for Hydrogen.N stands for Nitrogen.
Yes, you are right.
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
NH4+ is NH3's conjugate acid. NH3 accepts H+ to become a Bronsted-Lowry base.
No, hydrocarbons contain carbon (C) and hydrogen (H) NH3 is a compound of nitrogen and hydrogen.
ammonia (NH3) dissolves in water (H2O) to form ammonium hydroxide (NH4OH)
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
NH3
well NH3 is a base that reacts with H2O to get NH4 + OH- NH3+ H2O-->NH4+ + OH- A conjugate base is the species formed when a Bronsted- Lowry base accepts a proton. NH4+ is the conjugate acid of NH3
Ammonia (NH3) is composed from nitrogen (N) and hydrogen (H).
H bonds formed among NH3 molecules.Not inside a molecule.
NH3 is ammonia, and it does have covalent bonds between the N and the three H atoms.
Yes they form H bonds.They have enough electro negativity difference
Because it combines multiple atoms. N and H are atoms, but combined into NH3 they become a compound.
Yes, you are right.
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
Ammonium ions: NH3 + H+ --> NH4+
82.4% N and 17.6% H