it measures the magnitude of acceleration, but it can't tell you the direction of the acceleration.
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
deceleration can be measured from a velocity time graph by calculating the gradient of the velocity time graph if the V-t graph was linear. If the v-t graph was a curve then the differentiatial of the equation of the curve will give the deceleration variation with time.
if the segments on the disp vs time graph are straight lines, you merely measure the slope of those lines; the velocity is the slope of the lineso if the disp vs time graph shows a straight line of slope 3 between say t=0 and t=4, then you know the object had a constant speed of 3 units between t=0 and t=4;if the disp vs time graph is curved, then you need to find the slope of the tangent line to the disp vs time curve at each point; the slope of this tangent line is the instantaneous speed at the time, and with several such measurements you can construct your v vs t graph
To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.
straight line curve
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
You find the slope of the tangent to the curve at the point of interest.
It will measure acceleration in the direction towards or away from the origin.
No, it is instantaneous acceleration.
Tangent line is a graph. This graph is to gather data.
The answer will depend on the context. If the curve in question is a differentiable function then the gradient of the tangent is given by the derivative of the function. The gradient of the tangent at a given point can be evaluated by substituting the coordinate of the point and the equation of the tangent, though that point, is then given by the point-slope equation.
It is the instantaneous velocity, if it were a graph with velocity over time, then it would be acceloration
Slope = (vertical change)/(horizontal change), commonly referred to as rise/run. If the graph is a straight line, then you can count squares or measure how much change in vertical, over a specified change in horizontal. If it is a curve, then you need to have a tangent line (a line that touches the curve at a specific point and has the same slope as the line), then you can determine the slope of that line using the method described, above.
When you graph a tangent function, the asymptotes represent x values 90 and 270.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
The variable plotted along the vertical axis is the distance in the first case, speed in the second. The gradient of (the tangent to) the distance-time graph is the speed while the area under the curve of the speed-time graph is the distance.
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across