yes if you add two 20V/1W zener in parallel you will arrive 20V/2W
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The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
A watt is a measurement of Power (and a megawatt is a million watts) A volt a measurement of Electric Potential Difference The are related thus: W=VxA, or V=W/A So if you know the amperage, you can figure out the voltage: V = 3,400,000,000watts/?amps Your question is like asking how many feet are in an acceleration
W=wrought p=pipe b=bend
3w^2, because your multiplying 3w by 1w so you get 3w to the second power
It depends on how many Milliamp you push the 1w led. Most 1w leds are not 1w of power but less, so that they dont burn out fast. So the answer would not be 1w but truely less than 1w.
1hp = 0.7457 kW 1hp = 745.7 W 1W = 1.341 hp you can use these conversion factors
you can do a rescue job here is the wondermail: ??1W 1MF? 4R71 5.?3 6466 Q7?W hope this helps
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The coordinates 52N and 1W indicate a location in the United Kingdom, specifically in the eastern part of England.
MKS unit of power is "Watt 'W' (1W=1J/s)" CGS unit of power is "egr(cgs unit of work)per second"
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yes if you add two 20V/1W zener in parallel you will arrive 20V/2W
you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).
Three ranges.
1w+3w=2w