Yes it does. Velocity = Displacement / Time. On a graph of displacement vs time, the slope is the velocity. Steeper slope = higher velocity, flatter slope = lower velocity.
Acceleration
The Slope (which represents acceleration) of a constant velocity graph is Zero.
The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.
False. The slope of a velocity vs time graph is acceleration
no
Yes it does. Velocity = Displacement / Time. On a graph of displacement vs time, the slope is the velocity. Steeper slope = higher velocity, flatter slope = lower velocity.
Velocity is the slope of the position vs. time curve.
Acceleration
The Slope (which represents acceleration) of a constant velocity graph is Zero.
if there is a slope, the velocity is either increasing or decreasing. This is acceleration.
The slope of a time-distance chart would be a constant. The slope of a time-velocity chart would be 0.
If you are talking about a position vs time graph, the slope gives the average velocity. Velocity is displacement/change in time. (Change in position is displacement). Position is on the y axis and time is on the x axis. The slope = (y2-y1)/(x2-x1) = change in position/change in time = average velocity.
The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.
velocity.
The slope of a line on a velocity-time graph is acceleration.
the steeper the slope, the faster the velocity because the pull of gravity will be applied more since the resistance will be lower.