If a plus sign is missing before the 12, any value greater than or equal to 12.
If a negative sign is missing before the 12, any value greater than or equal to -12.
No. x2 -4x - 12 = (x + 2)(x - 6)
x2-4x-12 = (x-6)(x+2) when factored
x2 + 4x - 96 = (x - 8)(x + 12).
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function
x2+4x-12 = (x-2)(x+6) when factored
No. x2 -4x - 12 = (x + 2)(x - 6)
x2-4x-12 = (x-6)(x+2) when factored
x2 + 4x - 96 = (x - 8)(x + 12).
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
4x-x2 = 2
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
x2+4x-12 = (x-2)(x+6) when factored
If you are looking to factor this expression, then it does not have a real solution.
4x + 3 cannot equal 4x + 12:4x + 3 = 4x + 12 (given)3 = 12 (subtract 4x from both sides)
14
6