Pretty much all wires are made from materials with positive coefficient of thermal expansion - which means that as they are heated, they expand (get longer - as well as thicker). Most of the time the increase is a fairly small fraction, but for long lengths or large temperature increases, it can become significant.
The relationship is that as the current passing through the wire increases so does the heating effect in the wire. To see its effect just use the formula: W=I2R R is resistance in ohms I is current in amps W is the heat output in watts Hope this helps
Joule showed the heating effect due to the resistence of wire which cary the current.
Its elemental makeup. Its' diameter and its' length.
Yes ,due to heating effect of current.
it will not effect it because it only depends upon property of medium
When electricity passes through the wire of a light bulb, the resistance in the wire causes it to heat up through a process called Joule heating. This heating effect causes the wire to reach such high temperatures that it emits light and produces illumination in the bulb.
As the current flows through the wire it increases the kinetic energy by increasing the vibration of the metal atoms. i.e. it generates heat in the wire
By changing the length of wire, say reducing it, the resistance will drop and that will increase current flow but the voltage is less likely to change V=IR.
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
yes,joule is a heating reversible effect .
Normal household current is carried over a 10/2 wire. This is good to carry up to 20 amps. The more amps you wish to carry the larger the wire required. The smaller the number the larger the wire. 8/2 is larger than 12/2. outside of the "standard room temperature" of the resistance of a given size of wire there is something called "heating losses" in any given size of wire ... simply put, the resistance of a given length of wire increases as it's temperature increases... drawing current thru a wire causes a certain degree (no pun intended) of heating, thus raising the resistance and lowering the voltage/current available to the load... normally (with the proper size of wire for the length of run) these effects (rt resistance/heating losses) are minimal. another name for the heating losses is "IRsquared loss" .
how would you show the heating effect of a current?