32 feet / second / second.
Calculating the velocity of an object falling due to gravity is a complicated process because gravity decreases the further above the Earth you go. There is also a terminal velocity because of the viscosity of the air.
Simply though, acceleration due to gravity at the Earth's surface is roughly 9.8m/s2. This means, after 1 second, an object will have achieved a velocity of 9.8m/s.
The equation then if the viscosity of air and height above the Earth's surface are ignored is
V = 9.8 x S
Where V is the velocity and S is the number of seconds it has been falling.
The object opposes the air and while falling of the object the initial velocity will become zero , and the final velocity will have some value's this is how air will resist the velocity of falling object ...........
The speed when falling objects no longer accelerates due to air resistance is the maximum falling velocity.
Earth's gravity
terminal velocity is the final maximum velocity of a falling object.
a=change in velocity time
Acceleration:Always the same, doesn't need to be calculated. Acceleration of gravity = 9.8 meters (32.2 ft) per second2Acceleration of gravity is negative (points down).Velocity:(Initial velocity) + [ (acceleration) x (time) ]Positive velocity = moving upNegative velocity = moving down
The equation of motion is not modified. Net force = mass x acceleration, whether freely falling or not.
= Terminal velocity =
You can use the equation v = u + at from kinematics v = final velocity, which in this case is 0 because the object eventually hits the floor. u = initial velocity which is given to you a = acceleration which is always 9.8m/s^2 when dealing with falling objects t = time. manouver the equation and solve for time. Keep in mind that I havn't taken into account movement in the x-y direction and assumed that it is just a falling object falling in the -y direction. CG
terminal velocity
Slows an object down or speeds one up.
Until the object reaches it terminal velocity