bit size is a wordlength of one memory location
Generally, the bit size of a processor is indicated by the size of the accumulator, which is, most times but not always, the same as the internal data bus size. The 8086/8088 processor, for instance, is a 16 bit processor. The 8085 is an 8 bit processor. The 80386 is a 32 bit processor. The Q6600 Core2 Quad is a 64 bit processor. (These are just examples.)
The memory unit's size that depends on the processor is the bit.
The size of the accumulator is the same,means 64bit.
The Intel 80386 is a 32-bit processor.
The data path size for a 64-bit processor is 64 bits. This means it supports memory addresses, integer sizes and data paths that are 8 octets wide.
First off, I'm assuming you know what a microprocessor is. If not, please go look up that question (or, a related topic, the CPU (Central Processing Unit). 32 and 64 bits processors refer to the size of the native (default) word size in a processor. In a 32 bit processor, all basic operations happen on chunks of information 32-bits in size - information requiring more storage requires multiples of the 32-bit word. Likewise, 64-bit processors operate with a native size of 64-bit words. See the related question below for a more thorough explanation of the impact of 32 vs 64 bit native word size in a processor.
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64 bit. the size of accumulator will always equal to the size of processor. e.g 32 bit processor has 32 bit accumulator.-------------------------------------------------------------------------------------------------------------------------------------------Actually on some computers the accumulator(s) are larger than the processor word size. Some examples are:IBM 704, IBM 709, IBM 7090, IBM 7094 - these are 36 bit processors with a 38 bit accumulatorIBM 7030 - this is a 64 bit processor with a 128 bit accumulatorSome computers do not have accumulator(s), these fall into three main groups:Variable word length machines that store all data in main memoryGeneral purpose register machinesStack machines that either have a fixed sized internal stack or a variable sized stack stored in main memory
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
Because the processor is a 16 bit processor, and 64k is what you can address with a 16 bit processor.
Both. The Intel Core Duo was a 32-bit dual-core processor. The Intel Core 2 Duo is a 64-bit processor.
Q6600 is a 64 bit processor, but it can execute in 16 and 32 bit modes.