gravity
The Earth's gravity will force a round object to roll down an incline (slope).
Because the force of gravity is no longer straight down on the object, it is at an angle. thus when you have a ramp some of the force due to gravity is dispersed in the x plane, causing the force down on the y plane (vertical) due to gravity ( mass x gravity) to be less thus decreasing the amount of force needed to lift.
No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.
Weight, of the object is on dying bannanas.... quickly dying bannanas happy x-mas and!@#!@$!$#$#@4 you
because the force.......
The Earth's gravity will force a round object to roll down an incline (slope).
( Assuming mass of object on incline plane is in kilograms (kg) ) . Force pulling down incline on object (kilogram force) = object mass * sin (incline angle) . Force of object acting on and normal to incline (kilogram force) = object mass * cos (incline angle) . Mechanical Advantage = 1 / ( sin ( incline angle ) )
Because the force of gravity is no longer straight down on the object, it is at an angle. thus when you have a ramp some of the force due to gravity is dispersed in the x plane, causing the force down on the y plane (vertical) due to gravity ( mass x gravity) to be less thus decreasing the amount of force needed to lift.
Yes, if the incline angle becomes great enough. > As the angle increases, the force on the object down the incline increases but the effective weight on the slope surface decreases. > When the object breaks away the angle of incline can be used to calculate the coefficient of friction between the two surfaces. > coefficient of friction = sine ( incline angle ) / cosine ( incline angle )
Gravitational Potential Energy.
No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.
two, one is the resultant weight on the slope and = cosine (slope angle) * mass two is the force on the object and acts parralel to the the slope and = sin (slope angle) * mass
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The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.
because the force.......
mass of object *force of gravity
The amount of force which gravity pulls down an object is called its weight.