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What force is necessary to accelerate a 70-kg object at a rate of 4.2 ms?
Wiki User
∙ 7y ago
Force = mass x acceleration = 70 x 4.2 = 294 Newtons
Wiki User
∙ 7y ago
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What force is necessary to accelerate at 70kg object at a rate of 4.2 minutes per seconds?
Newton's 2nd law of motion states that F=ma Therefore, the force required is just the mass X the acceleration so 70 X 4.2 which equals a force of: 294 Newtons
Is it true that the attractive force of a 70kg person exerts on the Earth is smaller than the force the earth exerts on the person?
No, it is not. "For every action there is an equal and opposite reaction". The 70kg person is pulling just as hard on the Earth as the Earth is on the 70kg person, i.e. about 686 N.
What force is necessary to accelerate a 70 kg object at rate of 4.2 m s?
Force (in newtons) is equal to the mass of the object (in kilograms) multiplied by the acceleration of the object (in meters per second per second).F = maF = 0.04 x 20F = 0.8 newtons
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alot
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F=ma=70x9.8=686N
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How far will 70kg fall in 0.3 seconds?
It has been known since the 16th century that the mass of an object is irrelevant to how far it will fall. The main factor influencing the rate of fall is the shape of the object and, therefore, the air resistance (or buoyancy).
How much force does an 70 kg astronaut exert on his chair while sitting at rest on the launch pad?
a 70kg anything on the earth surface, that isn't subject to buoyancy, will exert 70kg times 9.8m/s/s newtons = 686 this is assuming his feet aren't touching the ground and his whole weight is supported by the chair of course.
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In uranus.....
