What is required is force on the inside of the lid of the box that is greater than the force of air pressure on the outside of the lid.
Pulling a box across ice requires less force than pushing the same box across carpet. This is due to the amount of friction between the carpet and box and the lack of friction between the ice and the box.
The force required to hold a 12 kg box off the ground would be equal to the weight of the box, which is calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). Therefore, the force required would be approximately 117.6 newtons.
The force required is 15 Newtons.
A joule is a neuton metre. i.e. 10*5 = 50 joules are required.
Work Done= Force applied x distance moved in direction of the force. so the work done should in this case be 40J
Air, unless it is an airtight box.
F=0.4(n) where f is force required to move box form resting (static) position and n is the normal force applied by the surface of the table. So F=.4x20kg=8kg. 8kg are required to overcome resisting force due to friction. 8kg=Appox. 78N. 78N of force is required to overcome resisting force due to friction.
Pulling a box across ice requires less force than pushing the same box across carpet. This is due to the amount of friction between the carpet and box and the lack of friction between the ice and the box.
Force required to move a box of the same weight changes in the case of different surfaces in contact due to friction.
The force required to hold a 12 kg box off the ground would be equal to the weight of the box, which is calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). Therefore, the force required would be approximately 117.6 newtons.
The force required is 15 Newtons.
It's 320 N. Since the friction force is in the direction opposite to the motion, thepulling force and the friction force balance, the net horizontal force on the box iszero, and its speed is therefore constant.
A joule is a neuton metre. i.e. 10*5 = 50 joules are required.
Work Done= Force applied x distance moved in direction of the force. so the work done should in this case be 40J
you could make it airtight or put lots of matresses on the walls
Please use the formula: work = force x distance
To remove the top cover you need to losen the clips around the box. there are 5 or 6 clips. push them in the middle with force, then they will come off. and the bottom part of the box you must take off the fresh air intake that comes from the radiator. just pull it out. And the bottom box itself sits in 3 rubber parts. pull the box agaist the engine. to the right of the car. must use force here as well.