What is required is force on the inside of the lid of the box that is greater than the force of air pressure on the outside of the lid.
The minimum force required to move the box can be calculated using the work done, distance, and weight of the box. Here, Work done = force * distance moved. So, force = work done / distance moved = 50J / 10m = 5N. Therefore, the minimum force required to move the box is 5 Newtons.
Pulling a box across ice requires less force than pushing the same box across carpet. This is due to the amount of friction between the carpet and box and the lack of friction between the ice and the box.
The force required to hold a 12 kg box off the ground would be equal to the weight of the box, which is calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). Therefore, the force required would be approximately 117.6 newtons.
To calculate the force of the box being slid across the floor, the person needs to know the mass of the box and the acceleration of the box. Using the equation F = ma (force equals mass times acceleration), the person can determine the force required to slide the box across the floor.
The work done to slide the box up the inclined plane can be calculated by multiplying the force required to push the box (275N) by the distance the box is being moved (3m). Therefore, the work done is 825 Joules.
The minimum force required to move the box can be calculated using the work done, distance, and weight of the box. Here, Work done = force * distance moved. So, force = work done / distance moved = 50J / 10m = 5N. Therefore, the minimum force required to move the box is 5 Newtons.
Air, unless it is an airtight box.
F=0.4(n) where f is force required to move box form resting (static) position and n is the normal force applied by the surface of the table. So F=.4x20kg=8kg. 8kg are required to overcome resisting force due to friction. 8kg=Appox. 78N. 78N of force is required to overcome resisting force due to friction.
Pulling a box across ice requires less force than pushing the same box across carpet. This is due to the amount of friction between the carpet and box and the lack of friction between the ice and the box.
It's 320 N. Since the friction force is in the direction opposite to the motion, thepulling force and the friction force balance, the net horizontal force on the box iszero, and its speed is therefore constant.
Force required to move a box of the same weight changes in the case of different surfaces in contact due to friction.
The force required to hold a 12 kg box off the ground would be equal to the weight of the box, which is calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). Therefore, the force required would be approximately 117.6 newtons.
To calculate the force of the box being slid across the floor, the person needs to know the mass of the box and the acceleration of the box. Using the equation F = ma (force equals mass times acceleration), the person can determine the force required to slide the box across the floor.
The work done to slide the box up the inclined plane can be calculated by multiplying the force required to push the box (275N) by the distance the box is being moved (3m). Therefore, the work done is 825 Joules.
The work done on the box is given by the formula work = force x distance. More information is needed to calculate the total work done on the box as the amount of force exerted to move the box is required.
To calculate the force needed, you'll need to know the acceleration due to gravity (9.8 m/s^2) and the distance the box is being pushed. The force required can be determined using the equation: force = mass x acceleration. In this case, the force required to push a 10 kg box 5 meters on a horizontal surface would be the force needed to overcome friction, which depends on the coefficient of friction and any other external forces acting on the box.
The work done to push the box can be calculated as the product of force and distance, so W = F * d. Plugging in the values, W = 5 N * 10 m = 50 Joules. Therefore, 50 Joules are required to push the box 10 meters with a force of 5 N.