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The strong force, which attracts neutrons and protons amongst themselves.
No, the particle has the following forces f= qvB= - qv.B + qvxB, the first force is a scalar force when the particle is parallel to the field and teh second force is avector force when teh particle is perpendicular to the field. If the particle is not neither parallel or perpendicular to the field, both the scalar and vector forces will be experiencd.
Acceleration and so a force acting on the particle.
If the motion of the particle is parallel to the direction of the field, then the force on the particle will be zero. This is an unstable condition, though. Even the slightest deviation from parallel will give a tiny force to the particle, which nudges it farther away from the parallel direction.
electrons
fully explain independent particle or single particle model as a factor responsible for nuclear stability
The photon is responsible for mediating the electromagnetic force. This includes both electricity and magnetism (both of which are manifestations of the electromagnetic force.) Interestingly, the photon is also the particle responsible for light, which is an electromagnetic wave.
Yes. It is commonly believed that the gravitational force is transferred through a particle called the graviton. This particle is hypothetical - it has not been observed yet.
The strong force, which attracts neutrons and protons amongst themselves.
Biasing of the transistor is responsible for stability of Q point.
Acceleration = force/mass
This particle is the electron.
The proton becomes a positron (charged particle without mass) which is then radioactively decayed. The same thing is beta capture which bands the nuclear strong force (a strong nuclear force) to decay the nucleus into a band of stability.
The proton becomes a positron (charged particle without mass) which is then radioactively decayed. The same thing is beta capture which bands the nuclear strong force (a strong nuclear force) to decay the nucleus into a band of stability.
Electron.
No, the particle has the following forces f= qvB= - qv.B + qvxB, the first force is a scalar force when the particle is parallel to the field and teh second force is avector force when teh particle is perpendicular to the field. If the particle is not neither parallel or perpendicular to the field, both the scalar and vector forces will be experiencd.
Yes. A single gas particle experiences gravitational force.