(Explanation) this is simply taking the ideal gas law PV=nRT, and dividing by P on both sides to isolate the V, kinda like solving an algebra problem
V=nRT/P
Apex
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
The formula is: T = PV/nR, Where: * T is the temperature in kelvin * P is the pressure in atmospheres * n is the number of moles * R is the gas constant
Approximately twice as much volume of hydrogen as of oxygen: Both gases are diatomic and nearly ideal at normal temperature and pressure, and the atomic ratio of hydrogen to oxygen in water is 2.
No. When water freezes and becomes ice, it expands. This causes it to have greater volume. If you were to melt down ice, the volume you would measure afterwards (in liquid form) would be lass than the volume of the actual solid ice.
V=nRT/P
Make V explicit in the general for of the gas law: P.V = n.R.T then you get V = (n.R.T) / P
Make V explicit in the general for of the gas law: P.V = n.R.T then you get V = (n.R.T) / P
Make V explicit in the general for of the gas law: P.V = n.R.T then you get V = (n.R.T) / P
(Explanation) this is simply taking the ideal gas law PV=nRT, and dividing by P on both sides to isolate the V, kinda like solving an algebra problem
(Explanation) this is simply taking the ideal gas law PV=nRT, and dividing by P on both sides to isolate the V, kinda like solving an algebra problem
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT