Since power is the product of voltage and current, you will need to find out the power rating of the headlamp when on low beam. To find the current, divide the power of the lamp by the voltage (12 V).
Current = (Voltage across the circuit) divided by (Total resistance of the circuit). The current is the same at every point in the series circuit.
Resistance of the circuit = (voltage across the circuit) divided by (current through the circuit)
we can calculate the current in a commmon electrical circuit by this formulae i.e,I=V\R where i is the current flowing in the conductor, R is resistance , V is the voltage.. THE FORMULA IS CORRECT but the term conductor does not suffice an explanation since a conductor is low in resistance R= resistance not conduction.
Motors are rated either in Watts or Amps, and by Voltage. If the motor is rated in Amps, that is the fuse or circuit breaker size you will need. If rated in Watts, you will have to use the formula P=IE, where P is power in Watts, I is current in Amps, and E is Electromotive Force in Volts. Since we know the watts and volts, we solve for current, thus: I=P/E, and I will be your current rating. One note: These calculations give the MINIMUM rating needed for the motor to run. Fuses and circuit breakers are usually designed so that they will break if the circuit pulls 250% of the Motor's rating.
One way to calculate current is using ohms law; current equals voltage divided by resistance or: I=V/R Where I is current, V is voltage and R is resistance.
Current = (Voltage across the circuit) divided by (Total resistance of the circuit). The current is the same at every point in the series circuit.
Phase angle is defined as the angle by which the load current leads or lags the supply voltage in an AC circuit. There are numerous ways to calculate a circuit's phase angle, so there is no 'formula' as such. For example, if you know a load's resistance and impedance, or its true power and apparent power, then you can use basic trigonometry to calculate the phase angle, and so on.
volts divided by resistance equals maximum amperage (current)
Jc=sigma.E
In 1957 Formula One Grand Prix was held at the Pescara Circuit in Italy which was 25.8 km long. The current circuit in the 2009 season is Spa-Francorchamps which is 7.004km long
to fine I (current) when you have R (resistance) and V (voltage) you use the formula: I = V / R
The formula you are looking for is Ohms = Volts/Amps. R = E/I.
i BELIEVE THAT THAT THE CHANGE IN CURRENT WITH THE ACKNOWLEDGEMENT TO TIME wHICH THE FORMULA= VL=is used
Resistance of the circuit = (voltage across the circuit) divided by (current through the circuit)
Use the formula: P=IR (power = current x resistance).
The current shortest circuit in Formula 1 is the Circuit de Monaco which hosted the Monaco Grand Prix. It's street circuit that runs 3.340 km (2.075 mi) around the famous principality and its the crown jewel of the Formula 1 season.*As of 2013
we can calculate the current in a commmon electrical circuit by this formulae i.e,I=V\R where i is the current flowing in the conductor, R is resistance , V is the voltage.. THE FORMULA IS CORRECT but the term conductor does not suffice an explanation since a conductor is low in resistance R= resistance not conduction.