pie chart
“What is the student enrollment (in the total number of students)?”
Combination; number of ways = 21
The BCeSIS number is a student number that is auto generated in BCeSIS. It is not the student's Personal Eduction Number or PEN #. The BCeSIS student number can be used to: *sort students *post marks without names *query students and much more. There is more information about this on the Integrated Service Website. (ISW)
13
the mathematical number is 31.5. Can you have half a student
Just like a clock face: 12 students.
Long Answer: I found it's actually more difficult to draw these 'students standing evenly spaced in a circle' problems with large numbers of students than it is to just develop a rule for the problem using more simplistic circles (such as a circle with four or eight students). Anyway a general rule for these problems is x+(1/2*t)=y, where x is the number of the particular student (1, in this case), t is the total number of students in the circle (must be an even number, otherwise they can't be standing directly opposite) and y will be the number of the student that the student you have picked is facing. Just a note that, obviously, if you picked student number 18 in this case, this would work out to student number 27. All you have to do in this case is subtract 18 from this number. So student number 18 would be facing student number 9. So if y in the above equation is greater than the total number of students, simply subtract the total number of students from the number you get. Short Answer: 1+(1/2*18)= 1+9 = 10 Student 1 will be facing Student 10.
A ten-digit number that is used to retrieve student records and provide various university services to students.
Any combination of 5 students leaves one student out. Since there are 5 possible students to leave out, the number of combinations of all but one student is 5.
No I am sure that college students do not have the average number of credit cards.
Student #10 is directly across from student #1. In order to evenly pair the sides of the circle, there must be 9 students in each hemicircle, across from the other 9, who will each have a number 9 higher. Student 10 is the first student of the second 9, numbers 10 through 18.
soution design and evaluation