Hi there! Assuming that the deceleration (or negative acceleration, if you will) is constant and the same in both cases, you can use a special kinematic formula to solve the problem. The formula follows:
(final velocity)^2 = (initial velocity)^2 + [ 2 * (deceleration) * (braking distance) ]
Rearranged to our needs the formula reads:
braking distance = [1/2] * -(initial velocity)^2 / (deceleration)
* this equation assumes that the final velocity is zero
If the initial speed were doubled then the general formula would read:
braking distance = 2 * -(initial velocity)^2 / (deceleration)
NOTICE that the two equations are the exact same except for the leading coefficients. 1/2 is assocaited with the braking distance of the normal velocity while 2 is assocated with the breaking distance of the doubled velocity. Since 2 is four times larger than 1/2, this leads us to the conclusion that the breaking distance for an object traveling at double a certain velocity would be 4x greater than the breaking distance of the object moving at the "regular" velocity.
When your speed is doubled, your braking distance is multiplied by four.
Yes
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Inertia.
Things that affect braking distance consist of the following factors: * speed at which you're travelling * weight of the car * road conditions * braking efficiency * friction between the road surface and your tires Things that affect braking distance consist of the following factors: * speed at which you're travelling * weight of the car * road conditions * braking efficiency * friction between the road surface and your tires
Hand-eye coordination, thinking distance, drunkenness, tiredness, if your on drugs, if your listening to music/being distracted. Thats just about it Also speed and road conditions affect braking distance
The speed; the quality of the braking system; the mass of the car; the time it takes the driver to notice a danger. The speed is especially important; other things being equal, braking distance is proportional to the square of the distance. That means that at twice the speed, the car will move 4 times as far while it brakes.
Because kinetic energy KE ~ V^2 (varies as the square of the speed). So ke ~ v^2 and KE ~ V^2 and when V = 2v, doubled, we have KE/ke = (V/v)^2 = (2v/v)%2 = 4 so that KE = 4 ke. QED. The new kinetic energy is four times the old. And, ta da, that means there is four times as much energy for the brakes to sap and reduce to zero kinetic energy, which means V = 0 is the end speed (stopped). So by the work function, which you should know by now, we have WE = FS where F is the braking force (friction) and S is the stopping distance. We assume the braking force remains the same for both speeds. Then KE - WE = 0, meaning the kinetic energy is sapped by the work so there is none left. And we have KE = WE = FS; so S = WE/F = KE/F and the stopping distance varies as the kinetic energy. So when the speed is doubled and the kinetic energy is quadrupled, the stopping distance is quadrupled because there is now four times as much kinetic energy to expend in stopping. QED.
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
First, you drive your vehicle at top speed on the road. Then, you step full brake. Next, you get out of the vehicle and take a measuring tape to measure the black trail left by your vehicle's tyres. the length you had measured is the braking distance.
Assuming a constant, linear deceleration, it takes four times the distance to stop when you double your speed. Using the formula v2 = u2 + 2as where v is final speed u is initial speed a is acceleration s is distance We can rearrange the formula to solve for s giving: s = (v2 - u2)/2a If we are finding the distance to that it takes to stop, the final velocity will be 0. Therefore distance to stop is given by s = -u2/2a Now we will look at the distance it takes to stop when speed is doubled. This will make our initial speed 2u. s = -(2u)2/2a = -2u2/a Comparing the two, we can see that when initial speed is doubled, it takes four times the distance to stop. (While it may look strange in the formula to have a negative sign in a distance measurement, remember that the car is decelerating, giving a negative acceleration. This means that the overall expression for distance will be positive.)
Mass will be doubled if the speed is 31/2/2 times the speed of light.