the vibreation goes round more
If both the length and mass of a simple pendulum are increased, the frequency of the pendulum will decrease. This is because the period of a pendulum is directly proportional to the square root of the length and inversely proportional to the square root of the mass. Therefore, increasing both the length and mass will result in a longer period and therefore a lower frequency.
the acceleration decreases
No, frequency does not depend on mass. Frequency is determined by the rate of vibration of an object and is independent of its mass.
If the mass of an object is increased while its volume remains constant, the density of the object will also increase. Density is defined as mass divided by volume, so an increase in mass with constant volume leads to a higher density.
Increasing the thickness of a vibrating string will decrease its frequency of vibration, as thicker strings have a lower natural frequency. This will result in a lower pitch when the string is played. Additionally, the thicker string will have a higher mass per unit length, which can impact how it interacts with the instrument and affect its overall sound.
lower mass = higher frequency
Increasing the mass of a pendulum will decrease the frequency of its oscillations but will not affect the period. The amplitude of the pendulum's swing may decrease slightly due to increased inertia.
Since Ek = 1/2 mv2 , That means that mass, velocity and the kinetic energy is directly proportional. So, if the mass and the velocity of the glider is increased so will be its Kinetic Energy of motion.
A decrease in mass of a system will increase the natural frequency of the system. This is because the natural frequency of a system is inversely proportional to the square root of the mass. So, as mass decreases, the natural frequency will increase.
A mass is hanging from a spring experiences the force of gravity.
The lower the frequency, the larger mass and longer length, The higher the frequency, the smaller the mass, and shorter the length.
The carts will be accelerated, by the force, a=F/m.