When frequency of a vibrating body becomes equal to its natural frequency the body starts vibrating vigorously due to resonance.
frequency is the inverse of time: 1/f=t therefore if you increase frequency by 3 the time (or cycle) will be 1/3
be more specific in your questions please
Let's say that that's what resonance is all about. Anyway, it need not be exactly the same frequency; just close enough.
Well, you basically already stated in your question what would happen. As a result of resonance, the second object will also vibrate.
The frequency, as observed by the receiving end, will be less than the frequency at which the wave was emitted.
frequency is the inverse of time: 1/f=t therefore if you increase frequency by 3 the time (or cycle) will be 1/3
be more specific in your questions please
Let's say that that's what resonance is all about. Anyway, it need not be exactly the same frequency; just close enough.
Well, you basically already stated in your question what would happen. As a result of resonance, the second object will also vibrate.
Frequency is set by the supply, not by the load.
Frequency - video game - happened in 2001.
I had that happen once. It turned out to be an earthquake.
Allele frequency is stable The phenotype frequency does not change.
Assuming this happens in phase, the pitch of the sound will increase. If only one of the loudspeakers does this, they'll be out of phase, which will initially sound like a slow pulsed beat, but eventually will form a chord.
The frequency, as observed by the receiving end, will be less than the frequency at which the wave was emitted.
the earth's frequency will rise
If the frequency stays the same, then the wavelength stays the same.