In order to answer that question, we need to know something about the two
circuits to which you're referring.
Specifically, their respective topological configurations would help us a bunch.
If the resistances to big in any circuit the circuit will become increasingly harder and eventually will break the circuit. An example of this is when the filament in an incandescent lightbulb burns out.
the circuit is broken.
The whole circuit fails - because the action of the bulb blowing cuts the circuit.
High skin resistance can produce severe skin burns but prevent the current from entering the body
It depends what is the outcome of burning. If that light has created open circuit, circuit will break and there will not be any current. But if there is short circuit means overall resistance is decreased. Thus current will increase. Besides overall brightness will also increase. Thus, if in a series lesser the number of bulbs more will be brightness.
In a series circuit, if one lamp burns out, it breaks the circuit, causing all the lamps to go out. This occurs because the current can no longer flow through the circuit due to the interruption. As a result, none of the other lamps will light up until the burnt-out lamp is replaced or the circuit is otherwise repaired.
What happens if one light bulb out burns out in set of lights in parallel circuit
What happens if one light bulb out burns out in set of lights in parallel circuit
how burns happens
it is dropped off the rocket and either burns in the atmosphere or lands in the ocean
If lamp C burns out in a circuit where lamps A and B are connected in series with lamp C, then both lamps A and B will also go out. This is because the circuit is incomplete when lamp C fails, preventing current from flowing through lamps A and B. In a parallel circuit, however, if lamp C burns out, lamps A and B would remain lit as they have alternative paths for current. The specific behavior depends on how the lamps are connected in the circuit.
In a series circuit, if one component burns out, the circuit will not work because the current flow is interrupted by the burnt-out component. This is because components in a series circuit share the same current.