KW = (sqrt 3) X Line voltage X Line current X Power factor
Line current is proportional to Line voltage for same KW load so if 220 motor is connected to 110 v the Line current will increase. see Example:
A 5 KW motor is connected to 220 V & then 110 v ( assume power factor is 0.850)
Current ( I with 220 v) = (5 X 1000) / (1.73 X 220 X 0.850) = 15.5 Amp
Current ( I with 110 v) = (5 X 1000) / (1.73 X 110 X 0.850) = 30.9 Amp
If you double the voltage (and the resistance stays constant), you will quadruple the wattage. Typically it will cause overheating and meltdown of electrical components, and anihilation of electronic components due to the avalanche breakdown.
The motor will run very fast and eventually smoke will come out of it. When the coils burn open, the motor will stop.
You can measure the current and power of a 'power supply', using an ammeter and a wattmeter. With the power supply connected to its load, the ammeter must be connected in series with the power supply's input. The wattmeter's current coil must also be connected in series with the power supply's input, and its voltage coil must be connected in parallel with the supply, taking the instrument's polarity markings into account.
It means that, to operate at its rated power, the appliance must be provided with a 230-V supply.
In an uninterrupted power supply there has to be a source of power when the electrical utility is not there. The only supply that is available is a battery that is in or connected to the UPS.
Appliances have to be connected in a parallel circuit to keep the voltages the same for each appliance (they were designed to work with one voltage) , this does not mean that the power output will be the same, the more appliances there are the more current (i.e. power) will be needed to for the appliances and this can go on until the grid cannot supply any more (and you blow a fuse)
What is the amount of power consumed by a 60 watt 220 volt lamp when it is connected across 110 volt supply?
Wattmeter is an intrument which is used to measure the power consumption of an Electric circuit or an appliance which is connected to the supply in terms of Watts.
No. You need a 3-phase supply that matches the voltage and current rating of your appliance.
Power consumed by the appliance = (DC supply voltage) x (DC current)
You can measure the current and power of a 'power supply', using an ammeter and a wattmeter. With the power supply connected to its load, the ammeter must be connected in series with the power supply's input. The wattmeter's current coil must also be connected in series with the power supply's input, and its voltage coil must be connected in parallel with the supply, taking the instrument's polarity markings into account.
power factor meters are connected across the supply
Its function is to supply electrical power via a plug that is plugged into it to supply an appliance.
It means that, to operate at its rated power, the appliance must be provided with a 230-V supply.
If the appliance is strictly resistive heating there will be no problem. If the appliance has a motor load connected with it, the unit will operate a bit slower and operate a bit warmer.
A 20-amp supply can be used for a 4400 watt appliance provided the voltage is 220 v or more, and the appliance is designed for the same supply votage, and the power factor is 1. On a 240 v supply the power factor must exceed 0.92.
Power supply units are rated based on their output and efficiency. When more equipment is connected, a higher output power supply is needed.
Nothing happens. The stereo has a transformer that converts the power to DC, and 50 or 60 Hz input makes no difference.
You need to convert the voltage if your appliance requires less voltage than you power supply. example: appliances is 110V and power supply is 220V.