If you don't change the voltage between the ends of the circuit,
then higher resistance in the circuit means lower current (amps).
You don't have enough information in your question, you need to include the voltage as well. One relevant equation is V = I * R where V: Voltage, I: Amps, and R: Resistance. When you have the voltage divide the Ohm resistance into that and you'll get your amps.
The amps (ampiers) decrease when in a series circuit ( with a light bulb)
Amps
The current (amps) will remain constant, but the voltage will drop.
Using Ohms law, the resistance can be calculated by using the following formulas. R = Watts/Amps (squared). R = Volts (squared)/Watts. R = Volts/Amps.
Increase resistance.
You use an "amp gauge" to measure amps in an actual circuit. It is hooked in series with the load. It can be placed anywhere in the circuit as long as it is hooked in series. Mathematically, you have to know the resistance, or wattage and voltage of a circuit. Volts=amps*resistance or amps=volts/resistance, or resistance=volts/amps. Ohms law!
Not necessarily. In a simple circuit V=IR, so if the resistance in a circuit remains constant, then voltage and current are directly proportional, so an increase in one will increase the other. If you were to change resistance and keep voltage constant, then the current would be inversely proportional to resistance, so as resistance went up, current would go down.
The resistance of the circuit will be 46 ohms
The equation that you are looking for is I = E/R. Amps = Volts/Resistance.
Depends on the voltage. Wattage is Volts x Amps. Resistance (ohms) is Volts divided by Amps. So on a 120V circuit, it would draw 41.66 amps. To do that, it would need a resistance of 2.88 ohms. But on a 240V circuit, it would draw 20.83 amps. That would require a resistance of 11.52 ohms. Determine the circuit voltage, then use that to figure the amps, then use that result to calculate the resistance necessary.
amps
If the cells are added in series, then the terminal voltage will increase, as would the internal resistance. If they are added in parallel, then the voltage would remain the same as for one cell, but the internal resistance would fall, and the available charge (in ampere hours) would increase.
What do you mean by energy? amps? Volts?, Either way if you have a series circuit with 3 loads in the circuit all voltage will be dropped proportionally to the loads resistance, if that makes any sense.
we can calculate the current in a commmon electrical circuit by this formulae i.e,I=V\R where i is the current flowing in the conductor, R is resistance , V is the voltage.. THE FORMULA IS CORRECT but the term conductor does not suffice an explanation since a conductor is low in resistance R= resistance not conduction.
Resistance of the circuit = (voltage across the circuit) divided by (current through the circuit)
Just use Ohm's Law Voltage = Current x Resistance Amps = Voltage Divided By Resistance Amps = 120 / 260