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Using Ohm's law E = I x R. R = E/I 120/10 = 12 ohms, I = E/R 120/6 = 20 amps. Resistance cut in half, current doubles.

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Q: How will the current change if the voltage in a circuit is held constant while the resistance halves?
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Related questions

If the resistance in a circuit is doubled while the voltage remains the constant the current is?

It is halved. coz voltage=current * resistance


If the voltage applied to a circuit remains constant and the resistance in the circuit is increased the current will?

V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease


How does current vary with the resistance in the circuit if the voltage is constant?

Inversely. As resistance increases, current dereases; given that the applied voltage is constant.


Will doubling the resistance in a circuit halve the current if voltage is held constant?

If resistance is halved while voltage remains constant, the current will double.


How the current in a circuit changes if the voltage in the circuit is decreased and the resistance remains the same?

If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.


The amount of current in a circuit can what by increasing the amount of resistance present in the circuit?

No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce


If the resistance decreases in a circuit when the voltage remains constant the current will?

Current will increase


When current remains constant and resistance increases the voltage in the circuit will?

The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.


What is the relationship among voltage circuit and resistance in a circuit?

Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)


What happens when you halve the resistance in a circuit when voltage remain constant?

Since resistance is the ratio of voltage to current, we can say that halving the resistance will result in twice the current.


If you double both the voltage and the resistance in a circuit what would be the effect on the current?

If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.


Will current increase if the voltage in a circuit is increased?

Ohm's Law states Voltage = Current x Resistance. Hence if voltage is increased and resistance is constant, current will increase proportionally to the rise in voltage.