No. A base decreases the amount of hydronium, and increases the amount of hydroxide.
A base added to water will increase the hydroxide ion concentration.
The hydroxide ion concentration in water increase.
It increases.
Sodium hydroxide simply becomes ionized in water, no reaction will occur. And the concentration of NaOH will be reduced, if enough water is added.
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
the calcium hydroxide will disolve while a bubbles appear
sodium acetate and water are formed.
Magnesium oxide react with water and magnesium hydroxide is formed.
Sodium hydroxide simply becomes ionized in water, no reaction will occur. And the concentration of NaOH will be reduced, if enough water is added.
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
A hydroxide ion.
the calcium hydroxide will disolve while a bubbles appear
The concentration of oxygen decrease.
The concentration of oxygen decrease.
the excess hydronium reacts with hydroxide in water to form more water and reduce the amount of hydroxide present.
sodium acetate and water are formed.
Magnesium oxide react with water and magnesium hydroxide is formed.
Aqueous ammonia is ammonium hydroxide NH4OH. When it is added to limewater which is actually calcium hydroxide Ca(OH)2 there will be no reaction.
Rubidium is highly reactive and if it is added to cold water there will be a large, exothermic reation; rubidium hydroxide and hydrogen are formed.
It reacts with water to form calcium hydroxide.