The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
If the quantity of gas is the same then the only way to increase the pressure is in fact to increase the temperature. So the temperature must increase in order for the pressure to increase. Another way of saying this is that if the pressure has increased then the temperature must needs also have increased.
The pressure will triple if the amount of the gas is tripled, but if the volume(the space it occupies) is tripled as the question asks, the pressure will decrease by 2/3. Tell that to the teacher.
Let's see with an example.
(1 atm)(1 liter gas)/(300 K) = (Xpressure)(3 liters gas)/(300 K)
900X = 300
X = 0.333 atmospheres
-------------------------------the pressure is reduced by 1/3
The pressure will be 3 times less, if the gas is "ideal".
This is according to PV=nRT.
Then the pressure will just decrease more (its the Boyle's Law).
Then the pressure of the gas would decrease signifigantly
Then the pressure would also triple.
Temperature will be increase
Assuming a fixed amount of an ideal gas kept at constant temperature, then the volume is reduced to a third of its former amount when the pressure is tripled. P V = n R T = constant = k P1 V1 = k = P2 V2 P2 = 3 P1 3 P1 V2 = P1 V1 V2 V1 / 3
The pressure is higher (x 3).
As a consequence of Boyle-Mariotte law: 166 cm3.
The electric force between two charged particles is inversely proportional to the square distance between them.Accordingly, it is reduced by a factor of 9
Temperature will be increase
PV=RT, if the volume is tripled at constant temperature, the pressure drops to one third.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
From Boyle's law pressure (P) times volume (V) divided by temperature T is a constant; so if T is held constant then if pressure triples volume is decreased to 1/3 its original value
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
0.667
Because of your mom
Assuming a fixed amount of an ideal gas kept at constant temperature, then the volume is reduced to a third of its former amount when the pressure is tripled. P V = n R T = constant = k P1 V1 = k = P2 V2 P2 = 3 P1 3 P1 V2 = P1 V1 V2 V1 / 3
Assuming the mass remains constant, the acceleration will be tripled as well.
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