Temperature will be increase
Assuming a fixed amount of an ideal gas kept at constant temperature, then the volume is reduced to a third of its former amount when the pressure is tripled. P V = n R T = constant = k P1 V1 = k = P2 V2 P2 = 3 P1 3 P1 V2 = P1 V1 V2 V1 / 3
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is higher (x 3).
As a consequence of Boyle-Mariotte law: 166 cm3.
The electric force between two charged particles is inversely proportional to the square distance between them.Accordingly, it is reduced by a factor of 9
PV=RT, if the volume is tripled at constant temperature, the pressure drops to one third.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
From Boyle's law pressure (P) times volume (V) divided by temperature T is a constant; so if T is held constant then if pressure triples volume is decreased to 1/3 its original value
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
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Because of your mom
Assuming a fixed amount of an ideal gas kept at constant temperature, then the volume is reduced to a third of its former amount when the pressure is tripled. P V = n R T = constant = k P1 V1 = k = P2 V2 P2 = 3 P1 3 P1 V2 = P1 V1 V2 V1 / 3
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
Assuming the mass remains constant, the acceleration will be tripled as well.
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