From Boyle's law pressure (P) times volume (V) divided by temperature T is a constant; so if T is held constant then if pressure triples volume is decreased to 1/3 its original value
If volume is held constant and pressure is tripled, the temperature will also triple according to the ideal gas law (PV = nRT). This relationship is known as Gay-Lussac's Law.
PV=RT, if the volume is tripled at constant temperature, the pressure drops to one third.
If the volume of a gas is tripled at constant temperature, according to Boyle's Law, the pressure of the gas will decrease by a factor of 3. This is because pressure and volume are inversely proportional at constant temperature.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
1/3 of the initial volume (Boyle-Mariotte law).
According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. So, if the pressure is tripled, the volume would become one-third of the original volume. Therefore, the new volume would be 0.33 L.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
Because of your mom
Assuming a fixed amount of an ideal gas kept at constant temperature, then the volume is reduced to a third of its former amount when the pressure is tripled. P V = n R T = constant = k P1 V1 = k = P2 V2 P2 = 3 P1 3 P1 V2 = P1 V1 V2 V1 / 3
Assuming the mass remains constant, the acceleration will be tripled as well.