1/3 of the initial volume (Boyle-Mariotte law).
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT
If the pressure on a gas is decreased, the volume of the gas will increase. This relationship is described by Boyle's Law, which states that at constant temperature, the pressure of a gas is inversely proportional to its volume. As pressure decreases, the gas particles have more space to move, causing an increase in volume.
According to Boyle's Law, as the volume of a gas decreases, the pressure increases, and vice versa. This is because the relationship between pressure and volume is inversely proportional when the temperature is held constant.
According to Boyle's Law, the pressure of a gas is inversely proportional to its volume when temperature is held constant. If the volume of a container is halved, the pressure will double. Therefore, if the initial pressure is ( P ) psi, the new pressure will be ( 2P ) psi after halving the volume.
PV=RT, if the volume is tripled at constant temperature, the pressure drops to one third.
Because of your mom
As a consequence of Boyle-Mariotte law: 166 cm3.
If the volume of a gas is tripled at constant temperature, according to Boyle's Law, the pressure of the gas will decrease by a factor of 3. This is because pressure and volume are inversely proportional at constant temperature.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
If volume is held constant and pressure is tripled, the temperature will also triple according to the ideal gas law (PV = nRT). This relationship is known as Gay-Lussac's Law.
According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. So, if the pressure is tripled, the volume would become one-third of the original volume. Therefore, the new volume would be 0.33 L.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The equation is P1V1=P2V2. (P1 is pressure before the change, P2 is the pressure after, V1 is the volume before the change, and V2 is the volume after it.) So to solve it, it would be the same change no matter how much the volume and pressure were to begin with. The values are P1= 1 atmosphere (the pressure of air at sea level) V1= 1 Liter which would mean P2=3 atmospheres 1*1=3(V2) 1/3 Liter= V2. So the volume would be one third of what it was before the pressure was tripled.
A [multiplicative] change in one dimension makes the same change in the volume. So the volume would be tripled.
From Boyle's law pressure (P) times volume (V) divided by temperature T is a constant; so if T is held constant then if pressure triples volume is decreased to 1/3 its original value
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT