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It becomes double as K=Q/t×L/A(T2-T1) so if the thickness (L) of an object is doubled the thermal conductivity will be doubled as thermal conductivity is directly proportional to the thickness/L of the object

K=L

K=2L,K=2 two times

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Guido Larkin

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Q: What happens to the thermal conductivity of the wall if its thickness is doubled?
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What happens to the thermal conductivity of a wall if its thickness is doubled?

It becomes double as K=Q/t×L/A(T2-T1) so if the thickness (L) of an object is doubled the thermal conductivity will be doubled as thermal conductivity is directly proportional to the thickness/L of the object K=L K=2L,K=2 two times


What happen to thermal conductivity of a wall if its thickness is doubled?

It becomes double as K=Q/t×L/A(T2-T1) so if the thickness (L) of an object is doubled the thermal conductivity will be doubled as thermal conductivity is directly proportional to the thickness/L of the object K=L K=2L,K=2 two times


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