The POP H instruction in the 8085 copies the top of stack to the HL register and then increments the stack pointer by 2. In C pseudo code, the sequence is L = *(SP++); H = *(SP++);
Stack/explicit.
To reset the pending RST 7.5 instruction in the 8085, you need to execute a SIM instruction with a particular value in the accumulator. PUSH FLAGS MVI A,10H SIM POP FLAGS Of course the PUSH and POP are optional, if you don't need to preserve the value of the accumulator.
The top of stack to copied to the specified register and the stack pointer is incremented by 2. A special form of POP, RET, has the program continuing with the popped address in the program counter, i.e. a return from subroutine or function call.
If this is a homework assignment, you really should try to answer it on your own first, otherwise the value of the reinforcement of the lesson due to actually doing the assignment will be lost on you.The call-return and push-pop instruction sequences on the 8085 are similar in that each pushes something on the stack and then pops something off the stack.In the case of call-return, that something is the program counter. In the case of push-pop, that something is up to the programmer, and it can be one of AF, BC, DE, or HL.
You would have to pop the stack into two dedicated memory locations in RAM, saving and restoring the register(s) used to do that, prefix those two locations with a JMP opcode, and JMP to the JMP.
; Exact answer: LXI H, FFFFH push H POP PSW
1. Memory Read - (PC) and then increment PC - Op Code C1 - Four clocks 2. Memory Read - (SP) and then increment SP - Transfer to C - Three clocks 3. Memory Read - (SP) and then increment SP - Transfer to B - Three clocks
stack segment register
Block transfer in 8085... PUSH FLAGS {optional, if registers need to be saved} PUSH B PUSH D PUSH H LXI H,COUNT LXI B,SOURCE LXI D,DESTINATION LOOP LDAX B STAX D INX B INX D DCX H MOV A,H ORA L JNZ LOOP POP H {optional, if registers need to be saved} POP D POP B POP FLAGS
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