It becomes unstable, so noble gases will not lose or gain electron
Calcium loses two electrons to obtain a noble-gas electron configuration.
Iodine accepts one electron to achieve noble gas configuration. Strontium loses two electrons to achieve noble gas configuration. Nitrogen accepts three electrons to achieve noble gas configuration. Krypton already has a noble gas configuration.
It accepts one electron.
The electron configuration and noble gas core for Li+ is that of He: Li+: (1s2, 2s0)
yes, Cu+ has a pseudo-noble-gas electron configuration
Potassium loses one electron to form K+ ion that has the noble gas configuration of the element neon.
Calcium loses two electrons to obtain a noble-gas electron configuration.
if lithium loses one electron it attains the stable noble gas electron configuration of helium. hence it is highly reactive.
Because calcium has 2 valence electrons, it needs to get rid of them to have a stable noble gas conformation. Chlorine atom has 7 VE and only needs to gain one electron to have the noble gas conformation. Therefore one calcium will give one electron to two chlorine atoms, therefore resulting in an ionic bond.
No. Calcium gains the noble gas configuration (octet) if it loses two electrons and not one.
Yes it does. Potassium has one valence electron. It loses this electron to from the cation, K+, thereby attaining stable noble gas configuration.
It accepts one electron.
Iodine accepts one electron to achieve noble gas configuration. Strontium loses two electrons to achieve noble gas configuration. Nitrogen accepts three electrons to achieve noble gas configuration. Krypton already has a noble gas configuration.
It accepts one electron.
It accepts one electron.
The "Noble gas electron configuration," or the condensed electron configuration, for F is [He] 2s2 3p5.
The number of electron shells depends on the noble gas. The number of shells will be equal to the period in which the noble gas is present.