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Aluminum loses 3 electrons. Since electrons have a negative charge losing them would make the aluminum atom lessnegative, which is positive. Hence, Al+3
+3
The ion of aluminium is 'three plus' Symbollically 'Al^(3+)'.
Aluminum loses three electrons to have a full valence shell. Oxygen gains two electrons to have a full valence shell. Aluminum Oxide is shown as Al2O3 because there are three oxygen atoms with a total of 6 gained electrons. Two Aluminum atoms lose 6 electrons and three Oxygen atoms gain six. This is the balance between aluminum and oxygen.
The +3 on aluminum refers to its oxidation number. The oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom. In this case, aluminum needs three valence electrons to form an octet (to have a total of eight valence electrons). If aluminum were to react with phosphate, PO4-3, the two would share their valence electrons and balance out, forming AlPO4.
Aluminum loses 3 electrons. Since electrons have a negative charge losing them would make the aluminum atom lessnegative, which is positive. Hence, Al+3
It would become an Aluminum ion that has a 3+ charge
Because there are 3 electrons in its outermost shell, to reach the nearest noble gas electronic configuration it loses 3 electrons .
+3
The ion of aluminium is 'three plus' Symbollically 'Al^(3+)'.
Because Aluminum has 3 valence electrons, so it has to lose 3 electrons to "become" a noble gas (to be stable), so it loses 3 negative, and becomes 3 positive.
The elemental state of aluminum tends to lose electrons. Its ionic state is 3+ which means it is most likely to lose up to 3 electrons.
Aluminum loses three electrons to have a full valence shell. Oxygen gains two electrons to have a full valence shell. Aluminum Oxide is shown as Al2O3 because there are three oxygen atoms with a total of 6 gained electrons. Two Aluminum atoms lose 6 electrons and three Oxygen atoms gain six. This is the balance between aluminum and oxygen.
The +3 on aluminum refers to its oxidation number. The oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom. In this case, aluminum needs three valence electrons to form an octet (to have a total of eight valence electrons). If aluminum were to react with phosphate, PO4-3, the two would share their valence electrons and balance out, forming AlPO4.
Aluminum has 3 valence electrons.
Aluminum has 3 valence electrons.
The answer is 3. Fe -> Fe3+ + 3e