A white precipitate of Silver Chloride is formed
8.44g
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
KAlSO42.12H2O + 2BaCl2 --> 2BaSO4 + KAlCl4
Rubidium chloride, RbCl, should be formed.
it produces a gas
it remains yellow i think me
9.11 g
When barium reacts with oxygen barium oxide is produced. Ba + O2 -> BaO
barium chloride reacts with a sulphate to produce barium sulphate which can be seen as a white precipitate and therefor identified.
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
8.44g
Yes, it is correct.
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
K2CO3 + BaCl2 = 2 KCI + BaCO3(s)
This equation is 3 BaCl2 + Al2(SO4)3 -> 3 Ba(SO4) + 2 AlCl3.
KAlSO42.12H2O + 2BaCl2 --> 2BaSO4 + KAlCl4
Rubidium chloride, RbCl, should be formed.