Dear Wiki Questioner,
When you disconnect a light bulb from a series circuit, the entire circuit is broken and no electricity can flow around it... so everything else on the circuit looses access to the power source!
You can think of a series circuit as a relay race, where the runners are the bulbs and wires (and anything else that is connected to the circuit). If any one of the runners in a relay race is taken out of the race (say by a sprained ankle), the relay gets stuck and the team cannot complete the race (that is to say, the electricity cannot make a complete circuit). Of course, if you plug that runner back into the system, the race continues as usual!
THE LIGHTBULB WILL
DISPLAY A DIM LIGHT.
The mirror will shoot the light the way it is pointing.
Then the light won't work!!but it does work..
when light hits a rough surface it scattters.
Reflection
im assuming that u meant "what happens when LIGHT hits a black surface?" the reason for this is that the black surface ABSORBS the light, and so none of the light waves can be reflected back (which is what makes it look black)
If they are connected in series if one light burns out, the whole string turns off.
the light bulb gives off more light
The circuit current is interrupted and all the lights will go out.
In that case, the entire circuit won't work.
Resistance is increased so the light will be dimmer.
They dim as the total resistance of series of resistances is the sum of the resistances; and current = V/R.
Nothing.
you can pull the fuse
You can not disconnect the check engine light.
The circuit will have the flow of electricity interrupted.
yes
If you unscrewed any bulb in the circuit it would turn all of the bulbs off.