volume increases faster than the surface area.
As the cell grows, the volume increases much more rapidly than the surface area.
volume
less
water
the volume
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
True! The volume increases more rapidly than the surface area.
Surface area of cell is divided volume of cell to get surface to volume ratio . If surface area is 8 cm2 and volume is 2 cm2 . The ratio would be 4:1 .
Larger cells will have a greater surface area-to-volume.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
The ratio decreases.
The ratio decreases.
it callapses
it decreases
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
True! The volume increases more rapidly than the surface area.
If the cell's surface-to-volume ratio got too small as a result of the volume increasing faster than the surface area, the cell would no tbe able to get the nutrients it needs to survive and would die.
true
As the cell grows larger the ratio of surface area to volume increases. Larger cell = more volume for the amount surface area.
A cell's volume is the amount of material that can fit into the cell. A cell's surface area is the total amount of material that makes up the outside of the cell. The ratio of surface area to volume is the amount of surface area per unit volume of an object or collection of objects.