the empirical formula and the molar mass
You can't without more information. You cannot go from the molecular weight of a compound to its formula without more information about what atoms it contains.See the Related Questions link to the left for a more detailed discussion of this.
The information about the actual molar mass is superfluous. Given any molecular formula, the corresponding empirical may be obtained by dividing all the subscripts in the molecular by the largest integer that yield an integer quotient for each subscript. In the given formula, the empirical formula is CH2.
the empirical formula and the molar mass
To find the molecular formula from the empirical formula, we need to know the molar mass of the empirical formula. In this case, the empirical formula's molar mass is 88. To find the molecular formula, we divide the given molecular mass (176) by the empirical formula's molar mass (88) to get 2. This means the molecular formula of Vitamin C is twice the empirical formula, so the molecular formula is C6H8O6.
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
You can't without more information. You cannot go from the molecular weight of a compound to its formula without more information about what atoms it contains.See the Related Questions link to the left for a more detailed discussion of this.
The information about the actual molar mass is superfluous. Given any molecular formula, the corresponding empirical may be obtained by dividing all the subscripts in the molecular by the largest integer that yield an integer quotient for each subscript. In the given formula, the empirical formula is CH2.
This is based upon the chemical characteristics of the elements that are present within the molecular formula.
the empirical formula and the molar mass
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
To find the molecular formula from the empirical formula, we need to know the molar mass of the empirical formula. In this case, the empirical formula's molar mass is 88. To find the molecular formula, we divide the given molecular mass (176) by the empirical formula's molar mass (88) to get 2. This means the molecular formula of Vitamin C is twice the empirical formula, so the molecular formula is C6H8O6.
The order of atoms in a molecular formula indicates the arrangement of different elements in a compound. The molecular formula provides information about the types and numbers of atoms present in a molecule.
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
To determine the molecular formula of a compound with a molecular mass of 132 amu, you would need additional information such as the elements present in the compound and their respective atomic masses. Without this information, it is not possible to determine the molecular formula.
C6H12O3 is a molecular formula that contains 54.5% C, 9.1% H, and 36.4% O and has molar mass of 132 amu.
The formula given is an approximate molecular formula for hexose sugars, which can have structural formulas distinct from one another.
Because an empirical formula is the simplest form of a compound, we know that the molecular formula contains more atoms than it does. Since we are given the molar mass, we can use this formula. x ( MM of empirical formula ) = MM of molecular formula MM of empirical formula = 12(2) + 1(6) + 16 = 46 MM of molecular formula = 138 46x = 138 x= 138 / 46 x=3 Therefore, the molecular formula is 3(C2H6O) that is C6H18O3