Math and Arithmetic
Algebra
Calculus

# What is -6y plus 7x equals -9?

It's the equation of a straight-line graph. Every point on the line is

a solution of the equation. There are an infinite number of them.

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## Related Questions

It does nothing! 4x + 6y = 24 7x + 6y = 9 Subtracting the first equation from the second gives: 3x = - 15 so that x = -5 Substituting the value of x in the first equation gives -20 + 6y = 24 so that 6y = 44 and so y = 22/3 or 71/3

The variables in the given expression are x and y

Subtract 7x from each side: 8 = -9 Not possible, game over.

Two ways to see this: 6y=8-9+6y 6y=6y-1 No answer here 6y= 8-(9+6y) 6y+(9+6y)=8 12y+9=8 12y=-1 y= -(1/12) or -0.08333...

No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...

7x + y + z = 6 7x + y + 4z = 9 y + x = 6 Take the first two statements and subtract them. 7x + y + z = 6 7x + y + 4z = 9 _____________ 0 + 0 - 3z = -3 Therefore: z = 1 Then you are left with: 7x + y + 1 = 6 7x + y + 4 = 9 which is impossible, so this is an impossible equation.

-8x+7 = -7x-2 -8x = -7x-2-7 -8x=-7x-9 -8x+7x=-9 -1x=-9 x=-9/-1 x=9

7x - 9 = 3x + 5 7x - 3x - 9 = 5 7x - 3x = 5 + 9 4x = 14 x = 14/4

-9x+6y = 54 6y = 9x+54 y = 1.5x+9 slope = 1.5

-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9

x2 + 7x + 9 = 3 &there4; x2 + 7x + 6 = 0 &there4; (x + 6)(x + 1) = 0 &there4; x &isin; {-6, -1}

11x+9=7x+21 11x-7x=4 4x+9=21 21-9=12 4x=12 12 divided by 4= 3 x=3

7x+3y where x=2 and y=9 can be written as (7*2)+(3*9) which can be simplified to (14)+(27), from there it's basic addition.

If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7

4x + y = 9 so that y = 9 - 4x 7x - 8y = 6 7x - 8*(9-4x) = 6 7x - 72 + 32x = 6 39x = 78 x = 2 Then y = 9 - 4x = 9-4*2 = 9-8 = 1

I don't know how, because I'm not good at math, but the answer is;79

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