### Perimetre of a rectangle given is 34mThe length of a diagnol given is 13mFind the dimensions?

In the rectangle ABCD, let the length be x, so the width will be 17 - x (17 = 1/2 of the perimeter). In the right triangle ABC, we have: 1. The length measure of AB = x (leg) 2. The length measure of BC = 17 - x (leg) 3. The length measure of AC = 13 (hypotenuse) From the Pythagorean Theorem we have: 13^2 = x^2 + (17 - x)^2 13^2 = x^2…

### How do you solve 2 - x 17?

Hope I'm right :P 2-x^(17) Since 2 does not contain x, the derivative of 2 is 0. (d)/(dx) 2-x^(17)=0+(d)/(dx) -x^(17) To find the derivative of -x^(17), multiply the base (x) by the exponent (17), then subtract 1 from the exponent. (d)/(dx) 2-x^(17)=0-17x^(16) Combine all similar expressions. (d)/(dx) 2-x^(17)=-17x^(16) The derivative of 2-x^(17) is -17x^(16). -17x^(16)