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This is a Ditloid. The answer is 1 step forward, 2 steps back.
To calculate the area of a triangle you can use three different methods. 1) Area = 1/2 base x vertical height. 2) Area = √[s(s - a)(s - b)(s - c)]. Where s = 1/2(a + b + c) and a,b and c are the lengths of the sides of the triangle. 3) Area = 1/2ab sin C = 1/2ac sin B = 1/2bc sin A. Where a, b and c are the lengths of the sides of the triangle and A,B and C are the angles opposite the side with the same (lower case) name.
The B-S- of A- with Brian Sack - 2011 1-2 was released on: USA: 18 November 2011
For finding the area of triangle with the help of Heron's formula: [s(s-a)(s-b)(s-c)]1/2 where a,b,c are sides of the triangle and s=1/2 of perimeter of the triangle
No. The B-2 is a modern bomber. The B-1 was not completed until 1980's and the B-2 even later.
The answer depends on what information you do have.Suppose you know only the lengths of the sides (a, b and c), then let s = (a + b + c)/2.Then area = sqrt[s*(s - a)*(s - b)*(s - c)]If 2 sides and the included angle, then area = 1/2*a*b*sin(C).There are other formulae.
L=sqr((1/2 a+b+c) * (s-a) * (s-b) * (s-c))
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
Here the sample space is(s)=10, =>mod(s)=10 a=be the event of getting exactly 5 boys =>mod(a)=5 b=be the event of getting exactly 5 girls =>mod(b)=5 thus, p(a)=mod(a)/mod(s)=5/10=1/2 p(b)=mod(b)/mod(s)=5/10=1/2 p(5 boys and 5 girls)=p(a)*p(b)=1/2*1/2=1/4
The two numbers are 18 and -24.If you're having trouble with the factoring, you can always use the quadratic formula:Let the two numbers be a & b. a*b = P and a+b = S {for Product and Sum}So substitute b = S-a {from the Sum formula}, and you have a*(S-a) = P, or:a*S - a² = P ----> a² - S*a + P = 0.So with the quadratic formula:a1 = (-S + sqrt(S^2 - 4*1*P)/(2*1) Anda2 = (-S - sqrt(S^2 - 4*1*P)/(2*1)Substituting -432 for P and -6 for S, we get a1 = 18, and a2 = -24. Note that substituting a1 into the original formulas, gives b = a2, or if you use a2, then you get b=a1. So the two numbers are a1 and a2.
s=(a+b+c)/2 inradius = √((s-a)(s-b)(s-c)/s) inradius for 3,4,5 = 1