4 x 50 = 200 5 x 50 = 250 40 x 50 = 2,000 45 x 50 = 250 + 2,000 = 2,250
set up a system of equations x+y=45 xy=200 set one equal to a variable x=-y+45 plug it into the other equation y(-y+45)=200 distribute the y -y2+45y=200 set it equal to 0 -y2+45y-200=0 take out the negative -(y2-45y+200)=0 factors of 200 are 1&200, 2&100, 4&50, 5&40, 10&20 5 and 40 = 45 factor -(y-5)(y-40)=0 solve for y y=5,40 this is the proper way to do this or you could just guess and check hope i helped :)
1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450 11 x 45 = 495 12 x 45 = 540
The first ten positive integer multiples of 45 are as follows: 1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450
200 divided by 45 is 4 with remainder 20.
.45 acre
90% of 45= 90% * 45= 0.9 * 45= 40.5
155
45 in 200 is 22.5%
4 x 50 = 200 5 x 50 = 250 40 x 50 = 2,000 45 x 50 = 250 + 2,000 = 2,250
200 is greater: 45% = 0.45
90 ! .45 * 200 = 90
(45 + 55) x 2 ie 200 m
The answer is 200% because 100% of 45=45 and 90 is two times 45 therefore it is 200%.
set up a system of equations x+y=45 xy=200 set one equal to a variable x=-y+45 plug it into the other equation y(-y+45)=200 distribute the y -y2+45y=200 set it equal to 0 -y2+45y-200=0 take out the negative -(y2-45y+200)=0 factors of 200 are 1&200, 2&100, 4&50, 5&40, 10&20 5 and 40 = 45 factor -(y-5)(y-40)=0 solve for y y=5,40 this is the proper way to do this or you could just guess and check hope i helped :)
1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450 11 x 45 = 495 12 x 45 = 540
is/of=%/100x/200=45/100cross products100x=200*45100x=9000divide each side by 100x=90Also, if 45% of 100 is 45 then twice that is 90.