25 Squares on a Bingo Card.
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
Let s = semiperimeter (ie half the perimeter) So s = (a+b+c)/2 = (5 + 8 + 11)/2 = 24/2 = 12 Then area = sqrt[s*(s-a)*(s-b)*(s-c)] = sqrt[12*7*4*1] = sqrt[336] = 18.33 square units.
Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12
If log10s = t, then t10 = s More generically: If logab = c, then ca = b
c=100+cY THEN WHICH ONE IS correct (a) S=100+0.2Y (B) C=100+0.8Y (C) S=100+0.8Y (D) C= 100+0.2Y i don't know just tell us
The ditloid 7 equals B for S B (7 = B for S B) means:7 = Brides for Seven Brothers
In order to find the radius of the inscribed circle we have to find the other side'lenght. We will use the property of the right triangle: c^2=a^2+b^2. In our case a = 8 (half of 16 since in this case the altitude is also a median) and b=15 ( the altitude). Using this formula we find that c^2=289 or c=sqrt(289) or c=17. Now that we know all the sides of the triangle we are going to use the following formula r=sqrt[(s-a)(s-b)(s-c)\s] where "r" is the radius of the inscribed circle and "s" is the semiperimeter of the triangle or s=a+b+c\2=16+17+17\2=50\2=25. Now substituting in the formula r=sqrt[(s-a)(s-b)(s-c)\s] we get r=sqrt[(25-17)(25-17)(25-16)\25]=sqrt[8.8.9\25]=sqrt[576\25]=24\5=4,8 . And so we have found the radius of the inscribed circle: r=4,8
four twice inside b and c SL 25 since
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
7=c(s) obviously
It depends on what B is and what S is!
16.5