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2 Humps on a Bactrian Camel
2 Hands on a Clock
2 Hulls on a Catamaran
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How do you differentiate x over 2?
f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2
What is the answer to h-3 equals -2?
-1
A right triangle has leg lengths 5 and 12 the length of the triangles hypotenuse h is?
Using Pythagoras' theorem the length of the hypotenuse is 13 units
What is the derivative of h to the negative 1 power?
d/dh(h^-1) = -1(h^-2) = -(h^-2)
Algebra answers 2h-2 equals?
Factor 2h−2 2h−2 =2(h−1) Answer: 2(h−1)
When h has the value of 17 calculate the value of h subtract 2?
15
How do you find the volume of water in a hemispherical bowl of radius A and depth H using integration?
Slice the bowl horizontally into circles, then integrate the area of the circles. The area of each circle is (pi * r^2). The height of each slice is dh. The 1st (bottom) circle is r=0. The r^2 of each circle-slice is (2*A*h-h^2), where A is the spherical radius, and h is the variable height of any given slice. At the top of the water level, (r^2=2*A*H-H^2). Integrate the area over the interval h=0->H as follows: V=pi * integral[(2*A*h - h^2) dh]; h=0->H to yield V=pi * (2*A*h^2 / 2 - h^3 / 3); h=0->H V=pi * (A*H^2 - H^3 / 3). As a check, plug the full diameter (2*A) in for H. If you did the integration correctly, you will get the full volume of the sphere, (4/3 * pi * A^3).
A dime and a penny are tossed and one dice is rolled what is the total number of possible outcomes?
There are 2 outcomes for the dime (H or T), 2 for the penny (H or T) and 6 for the die (1,2,3,4,5,6). In all, there are 2*2*6 = 24 outcomes. Some of them are given below in the pattern: dime, penny, die. The rest are easy to generate. [H,H,1], [H,H,2], ... , [H,H,6], [H,T,1], [H,T,2], ... [T,H,1], ... [T,T,1], ...
How do you keep the volume of a cylinder the same if the radius quadruples?
V = pi r^2*H & V = pi (4r)^2*h Equate pi r^(2)H= pi (4r)^2 h pi cancel down r^(2)H = (4r)^2h r^(2)*H = 16r^(2)*h 'r^(2) cancels down H= 16h h = H/16 This means is you increase the radius by '4 times' , then you reduce the height(H) by '16 times' in order to maintain the same volume.
On a right angled triangle what is the length of the hypotenuse if one side is 500 and the other is 300?
The length of the hypotenuse is: 583.1
What is the difference between multiplication and convolution?
multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].
The legs of a right triangle are 9 and 15 long what is the length of the hypotenuse?
[Hypotenuse]2 = 92 + 152 = 81 + 225 = 306 So hypotenuse = sqrt(306) = 17.49 to 2 dp
